Find the reverse number in C++

Write a function that takes an integer value and returns the number with its digits reversed. For example, given the number 12345, the function should return 54321.

Solution :

#include <iostream>
#include <iomanip>
using std::setw;
using std::setfill;
using namespace std;
int reverseDigits( int );
int width( int );
int main()
{
int number;
cout << "Enter a number between 1 and 9999: ";
cin >> number;
cout << "The number with its digits reversed is: " << setw( ( width( number ) ) ) << setfill( '0' ) << reverseDigits( number ) << endl;return 0;
}
int reverseDigits( int n )
{
int reverse = 0, divisor = 1000, multiplier = 1;
while ( n > 10 )
{
if ( n >= divisor )
{
reverse += n / divisor * multiplier;
n %= divisor;
divisor /= 10;
multiplier *= 10;
}
else
divisor /= 10;
}
reverse += n * multiplier;
return reverse;
}
int width( int n ) {
if ( n /= 1000 )
return 4;
else if ( n /= 100 )
return 3;
else if ( n /= 10 )
return 2;
else
return 1;
}

Output:

Enter a number between 1 and 9999:

8765
The number with its digits reversed is: 5678