4.24 C++ How to Program (8th Edition) By Paul Deitel, Harvey Deite

(Another Dangling Else Problem) Modify the following code to produce the output shown.
Use proper indentation techniques. You must not make any changes other than inserting braces. The compiler ignores indentation in a C++ program. 

We eliminated the indentation from the following code to make the problem more 
challenging. 

[Note: It’s possible that no modification is necessary.]

if ( y == 8 )
if ( x == 5 )
cout << "@@@@@" << endl;
else
cout << "#####" << endl;
cout << "$$$$$" << endl;
cout << "& & & & & " << endl;

a) Assuming x = 5 and y = 8, the following output is produced.

@@@@@
$$$$$
&&&&&

b) Assuming x = 5 and y = 8, the following output is produced.

@@@@@

c) Assuming x = 5 and y = 8, the following output is produced.

@@@@@
&&&&&

d) Assuming x = 5 and y = 7, the following output is produced.

[Note: The last three output statements after the else are all part of a block.]

#####$$$$$
&&&&&

Solution:

a)
if ( y == 8 )
if ( x == 5 )
cout << "@@@@@" << endl;
else
cout << "#####" << endl;
cout << "$$$$$" << endl;
cout << "& & & & & " << endl;
b)
if ( y == 8 ) {
if ( x == 5 )
cout << "@@@@@" << endl;
}e
lse{
cout << "#####" << endl;
cout << "$$$$$" << endl;
cout << "& & & & & " << endl;
}
c)
if ( y == 8 ) {
if ( x == 5 )
cout << "@@@@@" << endl;
}e
lse{
cout << "#####" << endl;
cout << "$$$$$" << endl;
}
cout << "& & & & & " << endl;
d)
if ( y == 8 ) {
if ( x == 5 )
cout << "@@@@@" << endl;
}e
lse{
cout << "#####" << endl;
cout << "$$$$$" << endl;
cout << "& & & & & " << endl;
}