Add time using structures in C++

Write a program having a structure named Time which has three integer data items i.e. hour, minute and second. The task is to add the variables of the Time data type though a function

void AddTime(Time *time1, Time *time2)

which takes as arguments the addresses of two Time type variables, adds these variables and stores the result in time2. The function must satisfy the following:
If second exceeds 60 then add 1 in minutes and subtract 60 from seconds.
If minute exceeds 60 then add 1 in hours and subtract 60 from minutes.
If hour exceeds 24 then subtract 24 from hours.

Test this function and print the result in the calling function.

#include<iostream>
#include<conio.h>
 using namespace std;
struct Time
{
int hour, minute, second;
};
void AddTime(Time *, Time * );
void main()
{
Time var1, var2;
for(int i=0;i<1;i++)
{
cout<<"for structure variable #"<<i+1<<" Enter the hours:";
cin>>var1.hour;
cout<<"for structure variable #"<<i+1<<" Enter the minutes:";
cin>>var1.minute;
cout<<"for structure variable #"<<i+1<<" Enter the seconds:";
cin>>var1.second;
cout<<endl<<endl;
cout<<"for structure variable #"<<i+2<<" Enter the hours:";
cin>>var2.hour;
cout<<"for structure variable #"<<i+2<<" Enter the minutes:";
cin>>var2.minute;
cout<<"for structure variable #"<<i+2<<" Enter the seconds:";
cin>>var2.second;
}
AddTime(&var1, &var2);
cout<<"\nNew hours = "<<var2.hour;
cout<<"\nNew minutes = "<<var2.minute;
cout<<"\nNew seconds = "<<var2.second;
cout<<endl;
}
void AddTime(Time *time1, Time *time2)
{
time2->hour += time1->hour;
time2->minute += time1->minute;
time2->second += time1->second;

if(time2->second > 60)
{
time2->minute += 1;
time2->second -= 60;
}
if(time2->minute > 60)
{
time2->hour += 1;
time2->minute -= 60;
}

if(time2->hour > 24)
{
.time2->hour -= 24;
}
}